theorem 8 ยง
- if AB and CD of a circle that cut at a point P (which may be inside or outside the circle), then PA x PB = PC x PD.
- case 1: the intersection point P is inside the circle.
- consider triangles APC and DPB
- โ APC=โ DPB (vertically opposite)
- โ CAB=โ BDC (angles in the same segment)
- thus triangle APC is similar to triangle DPB (AAA). This gives: - PDPAโ=PBPCโ - โดPAโ
PB=PCโ
PD
points are not labeled properly lmao
theorem 9 ยง
- consider triangles PAT and PTB
- โ ATP=โ TBA (alternate segment theorem)
- โ PAT=โ PTB (angle sum of a triangle)
- Therefore triangle PAT is similar to triangle PTB. (AA)
- This gives= - PTPAโ=PBPTโ - โดPT2=PAโ
PB
points are not labeled properly lmao
page 140 contains useful summaries of theorems you are expected to know
you do not need to know how to prove unless a question asks for you to explain it (which may be a possibility)